Integral sinxsin2xsin3x
NettetEvaluate : ∫sin(x+a)sin(x−a)dx. Hard Solution Verified by Toppr Let I=∫sin(x+a)sin(x−a)dx Put x+a=t, we have dx=dt I=∫ sintsin(t−2a)dt I=∫( sintsintcos2a− sintcostsin2a)dt I=cos2a∫dt−sin2a∫cottdt I=tcos2a−sin2a.log∣sint∣+C I=(x+a)cos2a−sin2a.log∣sin(x+a)∣+C Video Explanation Solve any question of Integrals with:- Patterns of problems > Nettet14. mar. 2024 · 1 Answer. +1 vote. answered Mar 14, 2024 by RahulYadav (53.5k points) selected Mar 14, 2024 by Prerna01. Best answer. Suppose I = ∫xe2x dx. On using integration by parts. ← Prev Question Next Question →.
Integral sinxsin2xsin3x
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Nettet12. apr. 2013 · 求sinxsin2xsin3x的不定积分的解答过程如下： 运用公式： sinα·sinβ=- (1/2) [cos (α+β)-cos (α-β)] sin2α=2sinαcosα 扩展资料： 积化和差公式： sinα·cosβ= (1/2) [sin (α+β)+sin (α-β)] cosα·sinβ= (1/2) [sin (α+β)-sin (α-β)] cosα·cosβ= (1/2) [cos (α+β)+cos (α-β)] 二倍角公式 sin2α=2sinαcosα tan2α=2tanα/ (1-tan^2 (α)) cos2α=cos^2 (α)-sin^2 …
NettetSolution ∫ sinx sin2x sin3xdx= 1 2∫(2sin3x sinx)sin2xdx [∵2sinAsinB= cos(A−B)−cos(A+B)] = 1 2∫ (cos2x−cos4x)sin2xdx= 1 4∫ 2sin2x cos2x−2cos4x sin2xdx = 1 4∫ … Nettet6. apr. 2024 · Hint – To find the integral of sinx .sin2x .sin3x, we simplify the term using trigonometric identities and then apply the formulas for integrals of sine and cosine …
NettetOldja meg matematikai problémáit ingyenes Math Solver alkalmazásunkkal, amely részletes megoldást is ad, lépésről lépésre. A Math Solver támogatja az alapszintű matematika, algebra, trigonometria, számtan és más feladatokat. Nettet30. mar. 2024 · Misc 7 - Chapter 7 Class 12 Integrals (Term 2) Last updated at March 30, 2024 by Teachoo. Get live Maths 1-on-1 Classs - Class 6 to 12. Book 30 minute class for ₹ 499 ₹ 299. Transcript.
Nettet16. jun. 2024 · Particular Integral (P.I.) So the general solution of the given differential equation is where are arbitrary constants. For the Particular Integral (i.e., P.I.) of trigonometric functions you have to follow the following rules: If can be expressed as and , then Note: If can be expressed as , then . . . where Share Cite Follow
Nettet= ∫ sin x sin 2 x ( 1 + 2 cos x) d x Let u=cosx ⇒du=−sinxdx Also, sin 2 x = 1 − cos 2 x = 1 − u 2 ∴ I = ∫ − 1 ( 1 − u 2) ( 1 + 2 u) d u = ∫ 1 ( 1 + u) ( 1 - u) ( 1 + 2 u) d u Using partial fractions, we get 1 ( 1 + u) ( 1 - u) ( 1 + 2 u) = A 1 + u + B 1 - u + C 1 + 2 u ⇒ − 1 = A ( 1 − u) ( 1 + 2 u) + B ( 1 + u) ( 1 + 2 u) + C ( 1 + u) ( 1 − u) how to pc vpn download in tamilNettet22. mar. 2024 · x = (kpi)/2 x = +- (2pi)/3 + 2kpi Use trig identity: sin a + sin b = 2sin ((a + b)/2).cos ((a - b)/2) In this case: sin x + sin 3x = 2sin (2x).cos (x) (sin x + sin 3x ... my body super simple songNettetAdım adım çözümleri içeren ücretsiz matematik çözücümüzü kullanarak matematik problemlerinizi çözün. Matematik çözücümüz temel matematik, cebir öncesi, cebir, trigonometri, kalkülüs konularını ve daha fazlasını destekler. how to pc to tv hdmi windows 10NettetSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. my body strong and goodNettet7. feb. 2024 · Integrate sin x . sin 2x . sin 3x + sec2 x . cos2 2x + sin4 x . cos4 x. indefinite integration jee jee main 1 Answer +1 vote answered Feb 8, 2024 by Sahilk (23.8k … how to pc to tv connectionNettet9. contoh soal dan pembahasan integral trigonometri; 10. contoh contoh soal identitas trigonometri; 11. Jelaskan tentang pembahasan identitas trigonometri; 12. tolong kasih contoh soal pembuktian identitas trigonometri beserta pembahasan yaa.. makasi; 13. tolong dong bikinin soal tentang bab identitas trigonometri sama pembahasannya; 14. my body sweats a lotNettet18. mai 2024 · Explanation: We want to find ∫ 1 1 +tanx dx. We start by substituting u = tanx and du = sec2xdx = (1 + tan2x)dx = (1 +u2)dx. So. ∫ 1 1 + tanx dx = ∫ 1 (1 + u)(1 +u2) du. Now we perform a partial fraction decomposition on the integrand. 1 (1 + u)(1 +u2) = A 1 + u + Bu + C 1 + u2. 1 = A(1 + u2) + (Bu +C)(1 + u) my body sweats too much